3x(2x-4)=6(x^2-36)

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Solution for 3x(2x-4)=6(x^2-36) equation: 



3x(2x-4)=6(x^2-36)

We move all terms to the left:

3x(2x-4)-(6(x^2-36))=0

We multiply parentheses

6x^2-12x-(6(x^2-36))=0



We calculate terms in parentheses: -(6(x^2-36)), so:

6(x^2-36)

We multiply parentheses

6x^2-216

Back to the equation:

-(6x^2-216)



We get rid of parentheses

6x^2-6x^2-12x+216=0

We add all the numbers together, and all the variables

-12x+216=0

We move all terms containing x to the left, all other terms to the right

-12x=-216

x=-216/-12

x=+18

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